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Basic probability question: dice

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Basic probability question: dice

Postby urbanbreez » Sun Mar 20, 2011 5:07 pm

If i have six dice, what is the percentage chance (probability) that i roll all 1's?

please show work.
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Re: Basic probability question: dice

Postby KCollins1304 » Sun Mar 20, 2011 5:14 pm

I think ((1/6)^6)*100%
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Re: Basic probability question: dice

Postby bigh0rt » Sun Mar 20, 2011 5:28 pm

1/46656
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Re: Basic probability question: dice

Postby urbanbreez » Sun Mar 20, 2011 6:01 pm

bigh0rt wrote:1/46656

how did you arrive at that answer?
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Re: Basic probability question: dice

Postby Inukchuk » Sun Mar 20, 2011 6:52 pm

The probability of rolling a 1 on 1 die is obviously 1/6. If you want a 1 on 2 dice, it's 1/6*1/6. 3 dice, 1/6*1/6*1/6, or (1/6)^3. Your'e looking for 6 dice, so it's (1/6)^6. If you wanted it as a percent, you multiply this by 100...
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Re: Basic probability question: dice

Postby Metroid » Sun Mar 20, 2011 6:54 pm

Do your own statistics homework. :-b
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Re: Basic probability question: dice

Postby bigken117 » Sun Mar 20, 2011 7:29 pm

bigh0rt wrote:1/46656


6*6*6*6*6*6
http://www.thebaseballcube.com/players/E/Jacoby-Ellsbury.shtml
http://www.fantasybaseballcafe.com/forums/viewforum.php?f=24
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http://www.facebook.com/pages/Fantasy-Baseball-Cafe/117034715055181?sk=wall
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Re: Basic probability question: dice

Postby urbanbreez » Sun Mar 20, 2011 7:47 pm

bigken117 wrote:
bigh0rt wrote:1/46656


6*6*6*6*6*6

ah, now that i can understand. thanks, fellas!
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Re: Basic probability question: dice

Postby Metroid » Sun Mar 20, 2011 8:03 pm

You're welcome. :-D
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Re: Basic probability question: dice

Postby urbanbreez » Sun Mar 20, 2011 8:16 pm

Metroid wrote:You're welcome. :-D

jerkface :-b
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