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Postby beatdrum » Mon Oct 04, 2004 12:16 am

This may have already been asked, and I may be missing something about tiebreakers, but...

What if the Giants had swept the Dodgers this weekend and tied for both the Wild Card and the NL West pennant? I understand about the tie breaker game on Monday against Houston, but how would the west be decided?
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Postby so0perspam » Mon Oct 04, 2004 12:18 am

Following is a listing of tiebreaking scenarios and game locations and times related to potential ties for the National League West Division Championship and/or National League Wild Card, according to Major League Rules 33 and 34.

Two-team tie for NL West (Los Angeles and San Francisco)
If there is a tie for a Division Championship and the winning percentage of the two tied Clubs is lower than the winning percentage of the second-place Club with the best record among all non-Division winners in the same League, the tie for the Division Championship shall be broken with a one-game playoff. The schedule for this tiebreaker as it relates to the National League West would be as follows:
Monday, October 4 - Los Angeles at San Francisco, 4:05 p.m. (EDT)

Two-team tie for NL Wild Card (Chicago, Houston or San Francisco)
A two-team tie for a Wild Card shall be broken with a one-game playoff. The schedules for the following potential tiebreakers would be as follows:
Monday, October 4 - Houston at San Francisco, 4:05 p.m. (EDT)
Monday, October 4 - Chicago at San Francisco, 4:05 p.m. (EDT)
Monday, October 4 - Chicago at Houston, 8:05 p.m. (EDT)

Three-team tie for NL Wild Card (San Francisco, Houston and Chicago)
If three Clubs are tied for first place in the Wild Card with an identical winning percentage at the conclusion of the championship season and the tied Clubs do not have identical records against one another in the championship season, they will choose a designation of Club "A," "B," or "C" based on their records in head-to-head competition during the championship season as follows:
If Club 1 has a better record against each of Clubs 2 and 3, and Club 2 has a better record against Club 3, then Club 1 shall choose a designation as Club "A," "B," or "C," and Club 2 shall choose a designation from the remaining two designations. Club 3 shall be assigned the remaining designation.

During a conference call held earlier today, San Francisco (4-2 vs. Chi; 4-2 vs. Hou) chose its designation a Club "C." Chicago (10-9 vs. Hou) chose Club "A" and Houston was assigned Club "B." Therefore, the schedule for this three-team tiebreaker scenario would be as follows:
Monday, Oct. 4 - Houston (B) at Chicago (A), 2:05 p.m. (EDT)
Tuesday, Oct. 5 - San Francisco (C) at Houston (B)/Chicago (A) winner, TBD
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