League Safe $50 Head to Head Points Based ESPN League

[jonwwf]

plz send the link for me!
jonwwf@yahoo.com

[bobacou]

I sent you an email with the link to the league. Who else wants in? The league is filling up quickly. Only a limited number of spots left.

[podoffdubs]

I have interest... What up "Im The Man"?! I know Jordan from basketball leagues.

mdhuysman@hotmail.com

[bobacou]

I sent you an email regarding the league. Who else wants in?

[RedsRocker]

Good active owners... apply here!
Only a few spots open now...

[khabibul35]

I'm very very interested and have been in a few Points league before. However, a strikeout for a hitter being worth as much 2 hits/2 walks is huge overreach. Even -.25 would be a big penalty against free swingers, but -1 would make guys like Reynolds unownable and put Stanton below 80th in rank and I feel like that would be travesty.

[Rmbxr9]

I'm very very interested and have been in a few Points league before. However, a strikeout for a hitter being worth as much 2 hits/2 walks is huge overreach. Even -.25 would be a big penalty against free swingers, but -1 would make guys like Reynolds unownable and put Stanton below 80th in rank and I feel like that would be travesty.

I'm in the league, and while at first what you said made me think, "Yeah... -1 for a K seems to high based on the other points." if you look at the projected totals using the league's scoring Stanton would be the #15th OF and #36 overall.

And that's with a 183 projected Ks.

ESPN has Stanton as the #21 OF in a Points League.
So, I don't think it's as skewed as you were saying.

Reynolds would be the #129 overall hitter. #18 at 3B, which is exactly where ESPN has him ranked in a standard points league.

Join us...

[bobacou]

Still a few more spots to fill in this active head to head points based league. Who wants in?

[rfdj65]

League sounds great. I'd love an invite. Plenty of experience with ESPN points leagues. Hit me with a PM if you've still got a spot...Ron

[bobacou]

I sent you a PM. Who else wants in?